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Doubt

If a constant be added or substracted from each of an AP then the resultant terms are also in AP. please solve this problem i dont have any idea about this

Answer Explanation

Sol. Let us take three terms in A.P i.e

a-d, a, a+d

Now if we add or subtract 1 in each term, then we have

[(a-d)+1] [a+1], [(a+d)+1]

Now , here if we subtract 1st term from 2nd&3rd, we will get''d''

Therefore, above three terms terms are also in A.P

Similarly when we subtract also,
[(a-d)-1],, [a-1] [(a-d)-1]

Hence, there three terms are also in A.P.

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